JavaScript/Notes/Function: Difference between revisions

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Created page with " == Assignment == === Function.prototype.call === 1) Convert a NodeList into an Array (Hint, see lesson 1 on Generics). var nodeList = document.body.childNodes; // your cod..."
 
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2) Find the latest and earliest date value in an array of Dates and construct a new Date object, respetively.
2) Find the latest and earliest date value in an array of Dates and construct a new Date object, respetively.
<source lang="javascript'>
var mon = new Date("December 02, 2013")
var mon = new Date("December 02, 2013")
var tue = new Date("December 03, 2013")
var tue = new Date("December 03, 2013")
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var dates = [ thu, tue, mon, sun, fri, sat, wed ];
var dates = [ thu, tue, mon, sun, fri, sat, wed ];
 
</source>
Hint, see: http://ecma-international.org/ecma-262/5.1/#sec-15.8.2.11
Hint, see: http://ecma-international.org/ecma-262/5.1/#sec-15.8.2.11

Revision as of 03:17, 2 December 2013

Assignment

Function.prototype.call

1) Convert a NodeList into an Array (Hint, see lesson 1 on Generics).

var nodeList = document.body.childNodes; // your code here! var nodeArray;

Function.prototype.apply

1) Write a `bind` function -- roll your own, or search MDN.

2) Find the latest and earliest date value in an array of Dates and construct a new Date object, respetively. <source lang="javascript'> var mon = new Date("December 02, 2013") var tue = new Date("December 03, 2013") var wed = new Date("December 04, 2013") var thu = new Date("December 05, 2013") var fri = new Date("December 06, 2013") var sat = new Date("December 07, 2013") var sun = new Date("December 08, 2013")

var dates = [ thu, tue, mon, sun, fri, sat, wed ]; </source> Hint, see: http://ecma-international.org/ecma-262/5.1/#sec-15.8.2.11